- 并查集专题
T2
- @ 2025-8-25 10:38:44
#include<bits/stdc++.h>
using namespace std;
const int N = 50010;
int fa[N], n, m;
int d[N];
int find(int x)
{
if(fa[x] != x) {
int u = fa[x]; //记录老的父节点
fa[x] = find(fa[x]);
d[x] += d[u];
}
return fa[x];
}
int main()
{
cin >> n >> m;
for(int i = 1; i <= n; i++) fa[i] = i;
int k, x, y, ans = 0;
while(m --)
{
cin >> k >> x >> y;
if(x > n || y > n) ans ++;
else
{
int fx = find(x), fy = find(y);
if(k == 1)
{
if(fx == fy && (d[x] - d[y]) % 3) ans ++;
else if(fx != fy)
{
fa[fx] = fy;
d[fx] = d[y] - d[x];
}
}
else {
if(fx == fy && (d[x] - d[y] - 1) % 3) ans ++;
else if(fx != fy)
{
fa[fx] = fy;
d[fx] = d[y] - d[x] + 1;
}
}
}
}
cout << ans;
return 0;
}
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